\(x^5+x+1\)

\(=x^5-x^2+x^2+x+1\)

\(=x^2\left(x^3-1\right)+x^2+x+1\)

\(=x^2\left(x-1\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)\)

\(=\left(x^3-x\right)\left(x^2+x+1\right)+\left(x^2+x+1\right)\)

\(=\left(x^3-x+1\right)\left(x^2+x+1\right)\)

gợi ý

biến x^2 = 2x^2-x^2

\(x^3+x^2+4\)

\(=\left(x^3+2x^2\right)-\left(x^2+2x\right)+\left(2x+4\right)\)

\(=x^2.\left(x+2\right)-x.\left(x+2\right)+2.\left(x+2\right)\)

\(=\left(x+2\right).\left(x^2-x+2\right)\)

\(x^8+x^4+1\)

\(=x^4.\left(x^4+1\right)+\left(x^4+1\right)-x^4\)

\(=\left(x^4+1\right).\left(x^4+1\right)-\left(x^2\right)^2\)

\(=\left(x^4+1\right)^2-\left(x^2\right)^2\)

\(=\left(x^4+1-x^2\right).\left(x^4+1+x^2\right)\)

\(x^4+2x^2-24\)

\(=x^4-4x^2+6x^2-24\)

\(=x^2\left(x^2-4\right)+6\left(x^2-4\right)\)

\(=\left(x^2+6\right)\left(x^2-4\right)\)

\(=\left(x^2+6\right)\left(x-2\right)\left(x+2\right)\)

x^4+x^2+1 = (x^4+2x^2+1)-x^2 = (x^2+1)^2-x^2 = (x^2-x+1).(x^2+x+1)

k mk nha

bạn ơi bạn chưa bớt 2x^2 kìa

ngu dốt

x⁵-x⁴-1=x⁵-x³-x²-x⁴+x²+x+x³-x-1

=x².(x³-x-1)-x.(x³-x-1)+(x³-x-1)

=(x³-x-1)(x²-x+1)

x^4+x^2+1 = (x^4+2x^2+1)-x^2 = (x^2+1)^2-x^2 = (x^2-x+1).(x^2+x+1)

k mk nha

mik chịu

\(x^4+1\)

\(=x^4+2x^2+1-2x^2\)

\(=\left(x^2+1\right)^2-2x^2\)

\(=\left(x^2-\sqrt{2}x+1\right)\left(x^2+\sqrt{2}x+1\right)\)

x³-3x²-4=